Q25 of 124 Page 1

The remainder when the square of any prime number greater than 3 is divided by 6, is

Any prime number greater than 3 is of the form 6k 1, where k is a natural number

and (6k 1)2 = 36k² 12k + 1 = 6k (6k 2) + 1

Thus, the remainder is 1.

If n is a natural number, then 9²ⁿ – 4²ⁿ is always divisible by

If n is any natural number, then 6ⁿ – 5ⁿ always ends with

The LCM and HCF of two rational numbers are equal, then the numbers must be

If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is