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1. Real Numbers
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Q24 of 124 Page 1

If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is

Let LCM be x and HCF be y.


Then, by given, x + y = 1260


Substituting x = 900 + y in above equation,


900 + y + y = 1260


900 + 2y = 1260


2y = 360


y = 180


Then, x = 900 + 180 = 1080


Thus, LCM = 1080 and HCF = 180


We know that for any two positive integers a and b, HCF (a, b) × LCM (a, b) = a × b.


1080 × 180 = 194400

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