Q11 of 124 Page 1

Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively.

The smallest number would be the LCM of 28 and 32


LCM of 28 and 32 = 224


Therefore the required smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively would be:


Number = LCM – (sum of the remainders)


⇒ 224 – (12 + 8)


⇒ 224 – 20 = 204


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