Q16 of 71 Page 418

In a p-n junction, the depletion region is 400 nm wide and an electric field of 5 × 105 V m–1 exists in it.

(a) Find the height of the potential barrier.


(b) What should be the minimum kinetic energy of a conduction electron which can diffuse from the n-side to the p-side.


Width of depletion region, d= 400 nm= 4×10-7 m

Electric Field, E= 5×105 Vm-1


(a) Let the height of potential barrier be V Volts.


We know that,


E=V/d


V=Ed


V=5×105×4×10-7


V=0.2 Volts


(b) The minimum kinetic energy required for diffusion of an electron from n-side to p-side


K.Emin= Potential barrier × Charge on an electron


= 0.2 V × 1.6 × 10-19 C


= 0.2 eV


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The potential barrier existing across an unbiased p-n junction is 0.2 volt. What minimum kinetic energy a hole should have to diffuse from the p-side to the n-side if

(a) the junction is unbiased,


(b) the junction is forward biased at 0.1 volt and


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In a p-n junction, a potential barrier of 250 meV exists across the junction. A hole with a kinetic energy of 300 meV approaches the junction. Find the kinetic energy of the hole when it crosses the junction if the hole approached the junction

(a) from the p-side and


(b) from the n-side