Q5 of 40 Page 1

If triangle ABC is right-angled at C, then the value of sec (A+B) is


We know that the sum of angles of any triangle is always equal to 180⁰.


Therefore, in above figure,


∴ ∠A + ∠B + ∠C = 180


∴ ∠A + ∠B + 90 = 180


∴ ∠A + ∠B = 90


∴ cos (A + B) = cos 90⁰ = 0



Therefore, sec (A+B) is not defined.


Hence, option d is the correct answer.

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