Given that √5 is irrational, prove that (2√5−3) is an irrational number.
OR
If HCF of 144 and 180 is expressed in the form 13m-16. Find the value of m.
Proof :
Given - √5 is irrational
To prove - (2√5−3) is an irrational number
Property - Rational number is one which can be represented in the form p/q, where q is not equal to 0.
Answer –
As given √5 is irrational.
Now, let us assume that (2√5−3) is a rational number.
We know that rational numbers can be represented in the form of p/q where p & q are integers and q is not equal to 0.
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In above equation p, q, 3, 2 are integers, hence
must be rational.
But √5 is irrational number.
Therefore, above equation is contradiction.
Hence, our assumption is false.
Therefore, (2√5−3) is an irrational number.
OR
m = 4
Given – HCF of 144 and 180 is 13m – 16
To find – value of m
Property –
HCF of two integers m & n is
HCF = m mod n , where m>n
(m mod n = remainder after dividing m by n)
Answer –
HCF of 144 and 180 is
180 mod 144 = 36
(we get 36 as a remainder after dividing 180 by 144)
But as given HCF of 144 and 180 is 13m – 16
∴ 13m - 16 = 36
∴ 13m = 52
∴ m = 4
Hence, the value of m is 4.
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