In the figure, if ∆ACB = ∆CDA, AC = 6 cm and AD = 3 cm, then find the length of AB.

12 cm
For ∆ACB & ∆ADC,
∠ CAB = ∠ DAC ………common angle
∠ ACB = ∠ CDA ………given
∴ ∆ACB ~ ∆ADC ………by AA test of similarity
………corresponding sides of similar triangles
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∴ AB = 12 cm
Hence, length of AB is 12 cm.
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