Calculate the number of atoms in 39.4 g gold. Molar mass of gold is 197g mole-1.
We know,
Molar mass=Mass of Avogadro’s number of atoms
=6.023×1023 atoms.
Given, mass of gold, m=39.4 g
Molar mass of gold=197g mole-1
Now,197 g of gold contain 6.023×1023 atoms
i.e. 1g of gold contain
atoms
∴ 39.4 g of gold contain
atoms = 1.20×1023 atoms
Couldn't generate an explanation.
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