A box of 1.00m3 is filled with nitrogen at 1.50 atm at 300K. The box has a hole of an area 0.010 mm2. How much time is required for the pressure to reduce by 0.10 atm, if the pressure outside is 1 atm.
Let
be the speed of molecule inside the box along x direction and n’ be the no. of molecules per unit volume.
The particle moving along the wall will collide in time Δt when the particles are at a distance
. Let A be the area of wall
Then, the no. of particle colliding in time Δt is
…(i)
The rms speed square towards x direction is equal to one third of speed
…(ii)
From kinetic theory of gases,
…(iii)
Using eqn.(ii)
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∴ No. of particles colliding in time Δt is given by using eqn.(i)

If initial no. of molecules colliding along the wall =n’
Finally no. of molecules colliding along wall
(Assume)
Net particle flow in time Δt
….(iv)
We know that by ideal gas equation
..(v)
Where μ =no. of moles of gas
And
…(vi)
n= no. of molecules of gas
using eqn.(vi) and (v) we get
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Let initial and final pressure of gas be p and p’ and let the pressure changes after time t’
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In time t’ no. of particles gone out is given by



Putting all the values, we get

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Therefore, time taken by pressure to reduce by 0.1atm is ![]()
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