Consider a rectangular block of wood moving with a velocity v0 in a gas at temperature T and mass density ρ. Assume the velocity is along x-axis and the area of cross-section of the block perpendicular to v0 is A. Show that the drag force on the block is 4ρ Avo
, where m is the mass of the gas molecule.
Given:
Velocity of rectangular block wrt. Gas =![]()
Temperature of gas=T
Mass density =ρ
Area of cross section of block = A
V=rms speed of gas molecules
Relative speed of molecules wrt front face=![]()
Momentum transferred to block in one collision![]()
m=mass of a single molecule
n=no. of molecules per unit volume
no. of collisions in time Δt
![]()
⇒ Momentum transferred from front surface in time Δt
![]()
Similarly, momentum transferred from back surface
![]()
Net force acting is equal to rate of change of momentum
i.e ![]()
![]()
From kinetic theory of gases
![]()

Therefore, force is given by

Which is the drag force acting on the particle
Couldn't generate an explanation.
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