Q48 of 97 Page 323

A uniform horizontal rod of length 40 cm and mass 12 kg is supported by two identical wires as shown in figure (15-E9). Where should a mass of 48 kg be placed on the rod so that the same tuning fork may excite the wire on left into its fundamental vibrations and that on right into its first overtone? Take g = 10 m s1.


We know that



Now, as per question,


fd =2f2


So,


Now,


12 = 48 + 12 = 60


By replacing the previous relation, we get that,


T1=48 N


T2=12 N


Now we need to take moment about point A,


T2 = 48x + 12(0.2)


So,


So,


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49

Figure (15-E10) shows an aluminium wire of length 60 cm joined to the steel wire of length 80 cm and stretched between two fixed supports. The tension produced is 40 N. The cross-sectional area of the steel wire is 10 mm2 and that of the aluminium wire is 30 mm2. What could be the minimum frequency of a tuning fork which can produce standing waves in the system with joint as a node? The density of aluminium is 26 cm3 and that of steel is 7.8 g cm3.


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