Q12 of 26 Page 1

Calculate E°cell for the following reaction at 25oC:

A + B2+(0.001 M) A2+(0.0001 M) + B


Given: Ecell = 2.6805, 1 F = 96500 C/mol


Given, Ecell = 2.6805


[B2+] = 0.001 M


[A2+] = 0.0001 M


A A2+ + 2e-


B2+ + 2e- B


A + B2+ A2+ + B


Ecell = E°cell – log


Where [P] is the concentration of ion in product side i.e. A2+ and [R] is the concentration of ion in reactant side i.e. B2+.


Ecell = E°cell – log


Substituting the values in above equation,


2.6805 = E°cell – log


E°cell = 2.6805 + 0.0295 (-1 log 10)


= 2.651 V


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