For the hydrolysis of methyl acetate in aqueous solution, the following results were obtained:

(a) Show that it follows pseudo first order reaction, as the concentration of water remains constant.
(b) Calculate the average rate of reaction between the time interval 20 to 40 seconds.
OR
(a) Define the following terms:
(i) Collision frequency
(ii) Rate constant (k)
(b) The rate constant of a first order reaction increases from 4
10-2 to 24
10-2 when the temperature changes from 300 K to 350 K. Calculate the energy of activation (Ea). (log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021, log 6 = 0.7782)
(a) [A]1= 0.40 mol L-1 at time = 0 seconds.
[A]2 = 0.20 mol L-1 at time = 20 seconds.
The rate constant (K) for a first order reaction is given as,
K = 
K = 
K = 0.034 sec-1
Now, at time = 40 s, [A]2 = 0.10 mol L-1
At time = 20 s, [A]1= 0.20 mol L-1
K = 
K = 
K = 0.034 sec-1
Since, the value of rate constant at any time is same i.e. 0.034sec-1. Therefore, the given reaction follows pseudo first order reaction.
(b) Average rate of reaction between the time intervals 20 to 40 seconds is
=
= 
= 0.005 mol L-1 sec-1
OR
(a) (i) Collision frequency is the no. of collisions per second per unit volume of reaction mixture.
(ii) Rate constant (k) is a proportionality constant that indicates the relationship between the molar concentration of reactants and the rate of a chemical reaction. Greater the rate constant, faster is the rate of reaction. It is generally given as K =
.
(b) Given, k1 = 4
10-2and k2 = 24
10-2
T1 = 300 K and T2 = 350 K
We know,
= 
log
= 
Ea = 31290.64 J/mol
= 312.9064 KJ/mol
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