Determine the type of cubic lattice to which ion crystal belongs if its unit cell has an edge length of 300pm and density of iron is 7.2g cm-1. [Atomic mass of Fe = 56 g mol-1; NA = 6.02 x 1023 mol-1]
Given: edge length = a = 300pm = 300 x 10-10 cm
Density = ρ= 7.2g cm-1
Atomic mass of Fe = M = 56 g mol-1
NA = 6.02 x 1023 mol-1

Where z = no., of atoms per unit cell

Since there are 2 atoms per unit cell, the ionic crystal is of body centre cubic(bcc) type.
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