Q13 of 26 Page 1

For a first order reaction, show that time required for 99% completion is double of the time required for the completion of 90% of reaction.

OR


The rate constant of a first order reaction increases from 4 x 10-2 to 24 x 10-2 , when the temperature changes from 300 K to 350 K. Calculate the energy of activation (Ea). [ Given: log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021, log 6 = 0.7782; R = 8.314 J/K/mol]


Time required=



From the above data we can confirm that for a first order reaction the time required for 99% completion is double the time required for the completion of 90% of reaction.


OR


Given: k1 =4 x 10-2 T1= 300 K


k2 = 24 x 10-2 T2= 350 K






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