Calculate the emf and
for the following cell at 298K:

OR
(a) Give reasons for the following:
(i) Iron does not rust even if zinc coating is broken in galvanized pipe.
(ii) Copper sulphate solution cannot be stored in zinc container.
(b) The molar conductivity of 0.025 mol L-1 methanoic acid is 46.1S cm2mol-1. Calculate its degree of dissociation and dissociation constant.
[Given: λoH+ = 349.6 S cm2 mol-1 ; λoHCOO- = 54.6 S cm2 mol-1]
cell reaction:![]()
Magnesium acts as anode while silver acts as cathode in this cell.
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OR
(a) (i) Zinc has a higher reduction potential than iron. Zinc comes higher up in the galvanic series. When zinc coating is broken in galvanized pipe a cell is formed such that zinc acts as anode (undergoes oxidation) while iron will be cathode, so iron does not undergo oxidation hence no rusting.
(ii) Zinc is more reactive than copper, so when copper sulphate solution is stored in zinc container zinc displaces copper to form zinc sulphate and precipitates copper. Hence copper sulphate solution cannot be stored in zinc containers.
(b) Concentration = C = 0.025 mol L-1
λHCOOH = 46.1 S cm2mol-1
λoHCOOH = λoHCOO- + λoH+ = 54.6 + 349.6 = 404.2 S cm2 mol-1
Degree of dissociation = α = λHCOOH / λoHCOOH = 46.1/404.2 = 0.114
Dissociation constant = 

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