Calculate the emf of the following cell at 250C:
Zn|Zn2+(0.001 M) || H+(0.01 M) | H2(g)(1 bar) | Pt(s)
E0(zn2+/Zn) = -0.76 V, E0(H+/H ) = 0.00 V
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= 0.00V – (-0.76V)
= 0.76V
By Nernst equation,
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= 0.7308V
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