(a) Define the following terms:
(i) Activation energy
(ii) Rate constant
(b) A first order reaction takes 10 minutes for 25% decomposition. Calculate t1/2 for the reaction.
(Given: log2 = 0.3010, log3 = 0.4771, log4 = 0.6021)
OR
(a) For a chemical reaction R → P, the variation in the concentration, ln[R] vs. time(s) plot is given as

(i) Predict the order of the reaction.
(ii) What is the slope of the curve?
(iii) Write the unit of rate constant for this reaction.
(b) Show that the time required for 99% completion is double of the time required for the completion of 90% reaction.
(a) (i) Activation energy is the energy required to form an intermediate (activated complex).
(ii)Rate constant of the reaction is defined as the rate of the reaction when concentration of each reactant is unity.
We know that, ![]()
When concentration of A and B is 1 then, Rate = k
(b) Given:
• T=10mins
• ![]()
For a first order reaction,
![]()
Substituting the given values,
![]()
We get k=4.79×10-4 s-1
For half life, ![]()
Substituting k in above equation we get,
![]()
![]()
OR
(a) (i) since R → P , it is a first order reaction.
(ii) Since the concentration is decreasing with type, slope is negative.
(iii) Unit of rate constant for 1st order reaction,
![]()
(b) For a first order reaction,
![]()
Rearranging we get,
![]()
Where
is the initial concentration of reactants and
is the concentration of reactants left unreacted.
Time required for 99% completion,
![]()
![]()
………………….(1)
Time required for 90% completion,
![]()
![]()
……………………….(2)
From equations (1) & (2) we can see that the time required for 99% completion is double of the time required for the completion of 90% reaction.
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