(a) A solution is prepared by dissolving 5.0 g of a non-volatile solute in 95 g of water. It has a vapour pressure of 23.375 mmHg at 25°C. Calculate the molar mass of the solute. Vapour pressure of pure water at 25°C is 23.75 mmHg.
(b) Give reasons for the following :
(i) Osmotic pressure is considered to be a colligative property.
(ii) Molality is a better option to express concentration in comparison to molarity.
OR
(a) Calculate the amount of CaCl2 (molar mass = 111 g/mol) which must be added to 500 g of water to lower its freezing point by 2K, assuming CaCl2 is completely dissociated.
(Kf For water = 1.86 K kg /mol )
(b)
(i) What happens when blood cells are placed in distilled water?
(ii) Why is increase in temperature observed on mixing chloroform with acetone?
(a) Given:
Mass Of Solute (W1) = 5.0 g
Mass of solvent (W2) = 95g
Vapour pressure of solution (p)=23.375mm Hg
Vapour pressure of pure water (P° = 23.75 mm Hg)
Molar mass of solute (M1) = ?
Acc to Raoults Law
P=P° A
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