Show that time required for completion of 3/4th reaction of first order is twice that of half-life
of the reaction.
OR
Derive integrated rate equation for rate constant of zero order reaction.
For a first order reaction the integrated rate eqauation are given as:
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Where,
t = time required for conc. change of [A]0 to [A]
[A]0 = initial concentration
[A] = final concentration
k = rate constant of reaction
Case I: at t = t1/2, [A] = [A]0/2
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Case II: at t = t3/4, [A] = (1-0.75) × [A]0 = 0.25[A]0
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Thus from both the cases we can say that
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OR
Consider the reaction,
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For a zero order reaction we know that the rate of the reaction does not depend on the concentration of the reactant. Thus the rate equation or rate law is given as:
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The sign is negative as the concentration of A is decreasing.
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Integrating both sides with limits,
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Thus the integrated rate equation for zero order is given as,
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Couldn't generate an explanation.
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