A. For the complex
. Write the hybridization, magnetic character and spin of the complex. ( Z = 27)
B. Why is the complex
more stable than the complex
?
Option (A) ![]()
Hybridization of ![]()
Co3+ is the central atom receiving a chloride ligand being the donor.

Since (F) is a weak field ligand according to the spectrochemical series of ligands, spin pairing of electrons does not occur in the lower d orbital and thus the higher energy orbitals are occupied. One s-orbital three p-orbital and 2 d-orbitals are used.


The structure is sp3d2 hybridisation and the said compound is paramagnetic.
Now the parallel spins can also be conversely proven by the paramagnetic properties shown by the said complex. The formation of outer d complex can be explained by Crystal Field Theory (CFT). According to valence bond theory this structure exhibits octahedral geometry.
Hybridization of ![]()
Co3+ is the central atom receiving a ethylenediammine ligand being the donor.

Since ethylene diamine (en) is a strong field ligand according to the spectrochemical series of ligands, spin pairing of electrons occurs and thus the lower energy orbitals are occupied. One s-orbital three p-orbital and 2 lower energy d-orbitals are used.


The structure is sp3d2 hybridisation and the said compound is paramagnetic in nature.
Now the parallel spins can also be conversely proven by the paramagnetic properties shown by the said complex. The formation of outer d complex can be explained by Crystal Field Theory (CFT). According to valence bond theory this structure exhibits octahedral geometry.
Option (B)
As the
exhibits spin pairing and the incoming ligands occupies lower energy orbitals the resultant energy of the compound is lower as compared to
. Thus the complex
more stable than the complex
.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.