Q16 of 26 Page 1

Calculate the freezing point of a solution when 3 g of CaCl2 (M= 111 g mol-1) was dissolved in 100 g of water, assuming CaCl2 undergoes complete ionization. ( Kf for water = 1.86 kg mol-1)

Given:


Weight of solute = 3 g = 0.03 kg


Weight of solvent = 100g = 0.1 kg


To find: freezing point of solution


We know that,




As CaCl2 dissociates in the solution the following reaction is considered.



So there are 3 ions


∴ i = 3


And for water Tf = 273 K






Freezing point of the solution is Tf = 271.64 K.


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