Q10 of 30 Page 1

A reaction is of second order with respect to a reactant. How is its rate affected if the concentration of the reactant is (i) doubled (ii) reduced to half?

If a reaction is of second order then,



So, rate equation stands as


Rate = k[A]2


Where k is rate constant.


So, according to the rate equation,


(i) If concentration of A is doubled, Rate increases 4 times.
(Putting the concentration of A = 2 in the rate equation as A stands for the concentration and it is doubled)


(ii) If concentration of A is halved, Rate becomes one-fourth times.
(Putting the concentration of A = 0.5 in the rate equation as A stands for the concentration and it is doubled).


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