Q14 of 27 Page 1

The rate constant of a first order reaction increases from 210-2 to 610-2 when the temperature changes from 300 K to 320 K. Calculate the energy of activation. (Given: log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021)

Given, rate constant, k1 = 210-2, T1 = 300 K


k2 = 610-2, T2 = 320 K


Using the formula, log = ()


log = ()


0.4771 = ()


Ea = 43848.485 J/mol


Ea = 43.84 KJ/mol


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