Q20 of 27 Page 1

(a) How will you convert the following: (i) Phenol to benzoquinone (ii) Propanone to 2-methyl propan-2-ol

(b) Why does propanol have higher boiling point than that of butane?


(a) (i)


2000px-PhenolOxidation.svg.png


(ii) OMgX OH


CH3COCH3 +CH3MgX → CH3-C-CH3→ CH3-C-CH3


(propanone)CH3 CH3


(2-methyl propan-2-ol)


(b) Propanol have higher boiling point than that of butane due to presence of hydrogen bonding between propane molecules whereas no such bonding is present in butane. Due to this propanol boil at higher temperature than butane.


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OR


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(a) What happens when D-glucose is treated with the following reagents: (i) HI (ii) conc. HNO3

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