Q4 of 101 Page 132

A block of mass 5.0 kg slides down an incline of inclination 30° and length 10 m. Find the work done by the force of gravity.

Weight of the body = 5× 9.8 = 49N (acting downwards) Now the displacement along the direction of force of gravity is given by = l× So the work done by the force of gravity = F.S = 49× 5=245J


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