Consider the situation shown in figure
(8-E8). Initially the spring is upstretched when the system is released from rest. Assuming no friction in the pulley, find the maximum elongation of the spring.

The maximum elongation of the spring is ![]()
Given
As shown in the diagram, the spring constant is given as “k”, and the mass of the block is given as “m”.
Formula Used
Using the conversation of mass, we equate the energies of spring compression and potential energy of the mass of the block, the formula of the energy stored in spring compression is
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And the energy stored in the block is formulated as
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where
The value of spring constant is denoted as “k”, the compression distance is “x”, the mass of the block is given as “m”, the gravity of the block is “g” and the height at which the block is kept is h.
Explanation
The h, in the potential energy of the block is given as x, equating the potential energy with the spring energy is
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Now we can say that the maximum elongation of the spring is
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Couldn't generate an explanation.
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