Q8 of 101 Page 132

A force F = a + bx acts on a particle in the x-direction, where a and b are constants. Find the work done by this force during a displacement from x = 0 to x = d.

Given the force displacement linear relation is F = a+bx Now the body moves in +ve X direction from x=0 to x=d So, at x=0 we have F=a, which we get from the linear relation and also at x=d we have = a+bd

Now by taking the average of forces at both the positions we get Avg force = (F+)/2



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