Q7 of 26 Page 1

Plot a graph showing variation of de-Broglie wavelength λ versus , where V is accelerating potential for two particles A and B carrying same charge but of masses m1, m2 (m1> m2). Which one of the two represents a particle of smaller mass and why?

Slope A is the smaller mass line.


The charge of mass and is denoted as “q”. Now showing the variation according to the de-Broglie’s wavelength we get:



where


is the de-Broglie’s wavelength, m is equivalent to the mass, q is the charge of the particle, v is the velocity of the charged particle.


Therefore, to find the slope of the de-Broglie’s wavelength, the graph (7.1) is depicted as



Hence, the slope of A is greater than B, as mass > because mass and wavelength is inversely proportional to each other and that’s why slope A is mass.


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