Two cells of emfs 1.5 V and 2.0 V having internal resistances 0.2 Ω and 0.3 Ω respectively are connected in parallel. Calculate the emf and internal resistance of the equivalent cell.
The EMF of the equivalent Cell is ![]()
The internal resistance of the equivalent cell is ![]()
Given
The EMF of the two cells are given as
and
, the internal resistance of the two cells are given as
and
respectively and are connected in parallel.
Formula Used
To find the effective EMF and internal resistance we use the formula of Effective Parallel EMF which indicates if the resistance is attached in parallel to each other between two voltage, the effective EMF is equivalent to the EMF acted by the load resistance and for the internal resistance, the internal load resistance is the ratio of the product resistance by sum of the resistance.
![]()
and
![]()
where
is the effective EMF,
and
are the EMF of the cells,
and
is the resistance of the cells,
is the internal resistance.
The EMF of
and
=
and
resp.
The internal resistance
and
respectively
The EMF of the 2 cells connected in parallel is
![]()
![]()
![]()
and
The internal resistance is
![]()
![]()
Therefore, The EMF of the equivalent Cell is
and the internal resistance of the equivalent cell is
.
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