Q9 of 26 Page 1

Two cells of emfs 1.5 V and 2.0 V having internal resistances 0.2 Ω and 0.3 Ω respectively are connected in parallel. Calculate the emf and internal resistance of the equivalent cell.

The EMF of the equivalent Cell is


The internal resistance of the equivalent cell is


Given


The EMF of the two cells are given as and, the internal resistance of the two cells are given as and respectively and are connected in parallel.


Formula Used


To find the effective EMF and internal resistance we use the formula of Effective Parallel EMF which indicates if the resistance is attached in parallel to each other between two voltage, the effective EMF is equivalent to the EMF acted by the load resistance and for the internal resistance, the internal load resistance is the ratio of the product resistance by sum of the resistance.



and



where


is the effective EMF, and are the EMF of the cells, and is the resistance of the cells, is the internal resistance.


The EMF of and = and resp.


The internal resistance and respectively


The EMF of the 2 cells connected in parallel is





and


The internal resistance is




Therefore, The EMF of the equivalent Cell is and the internal resistance of the equivalent cell is.


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