(i) An a.c. source of voltage V = V0 sin ωt is connected to a series combination of L, C and R. Use the phasor diagram to obtain expressions for impedance of the circuit and phase angle between voltage and current. Find the condition when current will be in phase with the voltage. What is the circuit in this condition called?
(ii) In a series LR circuit XL = R and power factor of the circuit is P1. When capacitor with capacitance C such that XL = XC is put in series, the power factor becomes P2. Calculate P1/P2.
OR
(i) Write the function of a transformer. State its principle of working with the help of a diagram. Mention various energy losses in this device.
(ii) The primary coil of an ideal step up transformer has 100 turns and transformation ratio is also 100. The input voltage and power are respectively 220 V and 1100 W. Calculate
(a) Number of turns in secondary
(b) Current in primary
(c) Voltage across secondary
(d) Current in secondary
(e) power in secondary
(i) The voltage the source is given as
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Now the current flowing in the circuit is
![]()
The peak voltage across Resistance is
![]()
The peak voltage across Inductor is
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The peak voltage is ahead of ![]()
The peak voltage across Capacitor is
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The peak voltage is behind by ![]()
The reactive voltage is represented by the difference of
![]()
Therefore, the voltage difference
) represented in terms of
we get
![]()
Now the impedance of the circuit is
![]()

![]()
Now if the value of
, the current and the voltage are in same phase.
Therefore, in such condition the circuit is called non-inductive circuit.
(ii) The ratio of the power factor![]()
Given
In a series LR circuit XL = R and power factor of the circuit is P1. XL = XC is put in series to capacitance as C, the power factor is P2.
Formula Used
The ratio between the resistance and the impedance formed in the circuit.
![]()
where
P is the power factor, Z is the impedance, R is the resistance.
When LR circuit XL = R and power factor of the circuit is P1
The value of the power factor ![]()

![]()
When XL = XC is put in series to capacitance as C, the power factor is P2.
The value of the power factor ![]()

Therefore, the ratio of the power factors is
![]()
OR
A transformer is a device which is used to change low alternating voltage to a high alternating voltage and again from high to low voltage. The working of transformer is done on mutual induction meaning a soft core iron is used which produces an alternating magnetic field which in turn produces alternating current on another coil.

The above diagram represents the working of a transformer, now as for the energy losses we have:
1. Flux leakage due to air induction in the coils and poor structure.
2. Loss of energy due to Eddy Current in case of lack or poor lamination of the coils.
3. Heating losses in resistance due to poor windings.
(ii) (a)
The number of secondary turns is ![]()
Given
The primary coil of an ideal step up transformer has 100 turns and transformation ratio is also 100. The input voltage and power are respectively 220 V and 1100 W.
Formula Used
The transformer ratio is equal to the ratio of the secondary winding number to the primary winding number which his given by
![]()
where
is the number of secondary winding and
is the number of primary winding, n is the transformer ratio.
Therefore, the number of secondary turns is
![]()
![]()
(b) The current in the primary coil is ![]()
Given
The primary coil of an ideal step up transformer has 100 turns and transformation ratio is also 100. The input voltage and power are respectively 220 V and 1100 W.
Formula Used
The power generated by the transformer is the product of current and voltage in the primary turning
![]()
where
is the primary current,
is the primary voltage, P is the power
The current generated in the primary core is
![]()
![]()
(c) the voltage in secondary coil is ![]()
Given
The primary coil of an ideal step up transformer has 100 turns and transformation ratio is also 100. The input voltage and power are respectively 220 V and 1100 W.
Formula Used
The transformer ratio is equal to the ratio of the secondary winding voltage to the primary winding voltage which his given by
![]()
where
is the voltage of secondary winding and
is the voltage of primary winding, n is the transformer ratio.
Therefore, the voltage in secondary coil is
![]()
![]()
(d) The current in the secondary coil is ![]()
Given
The secondary coil of an ideal step up transformer has 100 turns and transformation ratio is also 100. The input voltage and power are respectively 22000 V and 1100 W.
Formula Used
The power generated by the transformer is the product of current and voltage in the secondary turning
![]()
where
is the secondary current,
is the secondary voltage, P is the power
The current generated in the secondary core is
![]()
![]()
(e) In case of ideal transformer the power in the secondary coil = power in the primary coil = 1100 W
Couldn't generate an explanation.
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