Q10 of 40 Page 1

The chord of a circle of radius 10 cm, subtends a right angle at its centre. The length of the chord (in cm) is


By Pythagoras theorem,


AB2 = OA2 + OB2


⇒ OA = OB = 10 cm [Radii]


AB2 = 102 + 102


⇒ AB2 = 100 + 100 = 200


⇒ AB = 10√2

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