If x = 3 sinθ + 4 cosθ and y = 3 cosθ – 4 sinθ then prove that x2 + y2 = 25.
OR
If sinθ + sin2θ = 1;
Thenprovethatcos2θ+cos4θ= 1.
Given, x = 3 sin θ + 4 cos θ y = 3 cos θ – 4 sin θ
Taking LHS
x2 + y2 = (3 sin θ + 4 cos θ)2 + (3 cos θ – 4 sin θ)2
= 9sin2θ + 16cos2θ + 24sinθcosθ + 9cos2θ
+ 16sin2θ – 24sinθcosθ
= 9(sin2θ + cos2θ) + 16(sin2θ + cos2θ)
= 9 + 16 = 25 = RHS
OR
Given, sin θ + sin2θ = 1
⇒ sin θ = 1 – sin2θ
⇒ sin θ = cos2θ [1]
Taking LHS
cos2θ + cos4θ
= cos2θ + sin2θ [From 1]
= 1 = RHS
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.