In a family of three children, find the probability of having at least two boys.

OR

Two dice are tossed simultaneously. Find the probability of getting

(i) An even number on both dies.

(ii) the sum of two numbers more than 9.

If a family has three children total possible cases are

{GGG, GGB, GBG, GBB, BBB, BBG, BGB, BGG}

Total cases = 8

Cases having at least two boys

= {GBB, BBB, BBG, BGB} = 4

P(Getting at least two boy)

OR

When two dices are tossed,

Total outcomes = 36

(i) Favorable outcomes = {(2, 2), (2, 4), (2, 6), (4, 2), (4, 4), (4, 6), (6, 2), (6, 4), (6, 6)}

Number of favorable outcomes = 9

P(getting even number on both dies)

(ii) Favorable outcomes

= {(4, 6), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6)}

Number of favorable outcomes = 6

P(getting even number on both dies)