Q2 of 68 Page 15

A chord PQ of length 12 cm subtends an angle of 120° at the centre of a circle. Find the area of the minor segment cut off by the chord PQ.

Length of chord PQ = 12cm


Angle subtend at the center = 120°


Let radius of circle = r cm


Area of sector =


Length of triangle POQ = r cos 60



Length of base PQ = 2×RQ



Put value of r in respective place,


Area of minor segment = area of sector – area of ∆POQ






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