Find the area of the shaded region in Fig.15.72, if AC=24cm, BC=10cm and O is the centre of the circle.![]()

Given,
AC = 24 cm
BC = 10 cm
By Pythagoras theorem
AB2 = AC2 + BC2
= 242+102 = 576 + 100 = 676
AB =
= 26cm
Radius of semi-circle with diameter AB =
= 13cm
Area of semi-circle =
= 265.33cm2
Area of triangle ABC =
= 120cm2
So,
Area of shaded region = area of semi-circle – area of triangle
= 265.33 – 120 = 145.33 cm2
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