Q6 of 174 Page 594

























Marks



10



11



12



13



14



16



19



20



Number of students



3



5



4



5



2



3



2



1


We can draw the table in the given format
































































Marks (x)



Number of students (f)



Cumulative frequency



Fx



10



3



3



30



11



5



8



55



12



4



12



48



13



5



17



65



14



2



19



38



16



3



22



48



19



2



24



38



20



1



25



20




N = 25




∑fx = 332



We have;


N = 25 (odd number)


Median =


= value of 13th term


= 13


Now,


∑fx = 332 and ∑f = N = 25


Mean =


Hence,


Mode = 3(median) – 2 (mean)


= 3×13 - 2×13.28


= 39 – 26.56


= 12.44


More from this chapter

All 174 →
4

A cricket player scored the following runs in 12 one-day matches:

50, 30, 9, 32, 60, 50, 28, 50, 19, 50, 27, 35.


Find his modal score.


Calculate the mode of each of the following using the empirical formula.

 5

17, 10, 12, 11, 10, 15, 14, 11, 12, 13

 7

























Item (x)



5



7



9



12



14



17



19



21



Frequency (f)



6



5



3



6



5



3



2



4


 8























X



18



20



25



30



34



38



40



F



6



7



3



7



7



5



5