Q7 of 54 Page 312

tan (55° — θ) — cot (35° + θ) = θ

Consider L.H.S.

= tan (55° — θ) — cot (35° + θ)


= tan (90°-(35° +θ)) — cot (35° + θ)


= cot (35° + θ) - cot (35° + θ)


= 0


Hence, proved.


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