Q20 of 147 Page 159

Is the function defined by f (x) = x2 – sin x + 5 continuous at x = π?

It is given that f (x) = x2 – sin x + 5

We know that f is defined at x = π


So, at x = π,


f(x) = f(π) = π2 -sin π + 5 = π2 – 0 + 5 = π2 + 5


Now,


Let put x = π + h


If










Thus,


Therefore, the function f is continuous at x = π.


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