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5. Continuity and Differentiability
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Q3 of 147 Page 191

Differentiate w.r.t. x the function

(5x)3cos 2x

Let y = (5x)3cos 2x

Then log y = log (5x)3cos 2x


⇒ log y = 3cox 2x × log 5x


Differentiating both sides with respect to x, we get


[∵ ]


⇒


⇒


⇒


⇒


∴


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Questions · 147
5. Continuity and Differentiability
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