If y = (tan–1 x)2, show that (x2 + 1)2 y2 + 2x (x2 + 1) y1 = 2
: It is given that
y = (tan–1 x)2
On differentiating we get,
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Again differentiating, we get,
![]()
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So, (1+x2)2y2 + 2x(1+x2)y1 = 2
where, ![]()
Hence Proved
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