Find the second order derivatives of the functionx3 log x

Let us take y = x3 log xNow,= logx.3x2 + x3.1/x= logx .3x2 + x2= x2(1 + 3logx)Therefore,= 2x + 6xlogx + 3x= 5x + 6xlogx= x(5 + 6logx)

Q5 of 147 Page 183

Find the second order derivatives of the function
x³ log x

Let us take y = x³ log x

Now,

= logx.3x² + x³.1/x

= logx .3x² + x²

= x²(1 + 3logx)

Therefore,

= 2x + 6xlogx + 3x

= 5x + 6xlogx

= x(5 + 6logx)

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