Q13 of 147 Page 178

Find dy/dx of the functions.
y^x = x^y

Given: y^x = x^y

Taking log on both sides, we get

log y^x =log x^y

⇒x log y = y log x

Now, differentiate both sides with respect to x

Differentiate the functions given in w.r.t. x.

Find dy/dx of the functions.

x^y + y^x = 1

Find dy/dx of the functions.

(cos x)^y = (cos y)^x

Find dy/dx of the functions.

xy = e^{(x – y)}

Find dy/dx of the functions.yx = xy