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6. Application of Derivatives
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Q3 of 168 Page 211

Find the slope of the tangent to curve y = x3 – x + 1 at the point whose x-coordinate is 2.

The given curve is y = x3 – x + 1


Then, the slope of the tangent



= 12 -1 = 11


Therefore, the slope of the tangent 11.


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Questions · 168
6. Application of Derivatives
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 1 2 3 4 5 6 6 6 6 6 7 8 9 10 11 12 13 14 15 16 17 18 18 1 2 3 4 5 6 7 8 9 10 11 12 13 14 14 14 14 14 15 16 17 18 19 20 21 22 23 24 25 26 27 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5 6 7 8 9 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 3 3 4 4 4 5 5 5 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
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