Q1 of 168 Page 216

Using differentials, find the approximate value of each of the following up to 3 places of decimal.

Consider y = √x.


Let x = 25 and Δx = 0.3. Then, we get



Δy = √25.3 - √25


Δy = √25.3 – 5


Δy = √25.3 = Δy + 5


Now, dy is approximately equal to Δy and is given by:




= 0.03


Therefore, the approximate value of is 5.03.


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