The normal at the point (1,1) on the curve 2y + x 2 = 3 is

Q22 of 168 Page 242

The normal at the point (1,1) on the curve 2y + x² = 3 is

It is given that the equation of curve is 2y + x² = 3

Differentiating w.r.t. x, we get,

The slope of the normal to the given curve at point (1,1) is

Then, the equation of the normal to the curve at (1,1) is

⇒ y – 1 =1(x - 1)

⇒ y - 1 = x – 1

⇒ x – y = 0

The slope of the tangent to the curve x = t² + 3t – 8, y = 2t² – 2t – 5 at the point (2,– 1) is

The line y = mx + 1 is a tangent to the curve y² = 4x if the value of m is

The normal to the curve x² = 4y passing (1,2) is

The points on the curve 9y² = x³, where the normal to the curve makes equal intercepts with the axes are