Using differentials, find the approximate value of each of the following up to 3 places of decimal.
Consider y = 
Let x = 0.008 and Δx = 0.001. Then, we get
Δy = (x+∆x)1/3 - (x)1/3
= (0.009)1/3 - (0.008)1/3 = (0.009)1/3 - 0.2
= (0.009)1/3 = Δy + 0.2
Now, dy is approximately equal to Δy and is given by:
= 0.008
Therefore, the approximate value of 
is 0.008.
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