A carboxylic acid C2H4O2 reacts with an alcohol in the presence of H2S04 on form a compound 'X'. The alcohol on oxidation with alkaline KMn04 followed by acidification gives the same carboxylic acid, C2H402. Write the name and structure of (i) Carboxylic acid, (ii) alcohol and(iii) the compound 'X'.
As given in question when carboxylic acid reacts with an alcohol in presence of Sulphuric acid:
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(i) The name of the carboxylic acid is Ethanoic Acid and its structure is as follows:
CH3COOH:

(ii) The name of the Alcohol is Ethanol and its structure is C2H5OH:

(iii) The compound X will be Ester. (CH3COOC2H5) i.e. Ethyl Ethanoate. The structure is:

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