Q2 of 47 Page 1

The tops of two towers of height x and y, standing on level ground, subtend angles of 30 � and 60 � respectively at the center of the line joining their feet, then find x : y.


Let AB and CD be the two towers of x and y heights respectively.


Let O be the center of AC. OA = OC = p(let)
∠AOB = 30° (given)


∠COD = 60° (given)


In Δ AOB,
⇒


⇒ h = x√3 ….(1)


In ΔCOD,


⇒
⇒ …(2)


From eq (1) and (2), we get



⇒


∴ x:y = 1:3


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