Water is flowing at the rate of 2.52 km/hr. through a cylindrical pipe into a cylindrical tank, the radius of whose base is 40 cm. If the increase in the level of water in the tank, in half an hour is 3.15 m, find the internal diameter of the pipe.
Volume of water through pipe = Volume of water in the tank
Radius of the tank(R) = 40cm = 0.4m
Increase in height(H) = 3.15m
Volume of the water in the tank = ![]()
Let r be the internal radius of the pipe.
Velocity of water = 2.52km/hr
In half hour, distance travelled(L) = 2.52/2 = 1.26km = 1260m
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Volume of water through pipe = Volume of water in the tank
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ r = 0.02m = 2cm
∴ Diameter of the pipe = 4cm
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